The net force exerted on the 2.0 kg object by the 3.0 kg object is 14 N.
What is the net force acting at the end of the 3.0 kg object?
The net force acting on the 3.0 kg object is determined as follows:
- Net force = applied force - frictional force
Frictional force on acting on the 1.0 kg object = 0.2 * 1.0 * 10 = 2 N
Net force = 24 - 2 = 22 N
Net force acting at the end of the 2 kg object is determined as follows:
Net force = applied force - frictional force
Frictional force on acting on the 1.0 kg and 3.0 kg object = 0.2 * 4.0 * 10 = 8 N
Net force = 22 - 8 = 14 N
Therefore, the net force exerted on the 2.0 kg object by the 3.0 kg object is 14 N.
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