Question

Solve the following quadratic function
by utilizing the square root method.

Answer 1

The value of x = ±$\sqrt{64-y} /4$

Given: y= 64 - 16$x^{2}$

⇒ 64 - 16    $x^{2}$ - y = 0

- 16    $x^{2}$ +64 - y = 0

x= 0 ± √(-4)(-16)(64-y)/2(-16)

x= 0 ± √64(64-y)/2(-16)

x= 0 ± 8√(64-y)/-32

x=  8√(64-y)/-32

⇒The value of x = ±$\sqrt{64-y} /4$

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