The final temperature of the gas given the data from the question is 1527 °C
The final temperature of the gas can be obtained by using the Charles' law equation as illustrated below:
V₁ / T₁ = V₂ / T₂
V / 300 = 6V / T₂
Cross multiply
V × T₂ = 300 × 6V
Divide both side by V
T₂ = (300 × 6V) / V
T₂ = 1800 K
Subtract 273 from 1800 K to express in degree celsius
T₂ = 1800 – 273
T₂ = 1527 °C
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