Question

A bag held 3 red marbles, 1 blue marble, and 4 yellow marbles. Lee drew a red marble and did not replace it. What is the probability of drawing a yellow marble next?
A.1/4
B.1/3
C.1/2
D.4/7

Answer 1

Answer: D.4/7

Step-by-step explanation:

     First, we will find out how many marbles are in the bag.

3 red + 1 blue + 4 yellow - 1 red = 2 red + 1 blue + 4 yellow = 7 marbles

     Now, we will put wanted outcomes over possible outcomes.

$\displaystyle \frac{\text{wanted outcomes, yellow marbles}}{\text{possible outcomes, marbles in the bag}} =\frac{4\text{ yellow}}{\text{7 marbles}} =\text{D. 4/7}$

Answer 2

Answer:

The answer is 4/7

D