Question

6^2-4(3-√25)^2/|4-8|
the answer is 5 but im not sure on the steps and how to get 5, please help tysm :)

Answer 1

I'm going to assume you start with

$\dfrac{6^2 - 4 (3 - \sqrt{25})^2}{|4 - 8|}$

Let's simplify some pieces of this:

$6^2 = 6\times6 = 36$

$\sqrt{25} = \sqrt{5^2} = 5$

$(3 - \sqrt{25})^2 = (3 - 5)^2 = (-2)^2 = (-2)\times(-2) = 4$

$|4 - 8| = |-4| = 4$

So as a first step we can reduce this to

$\dfrac{6^2 - 4 (3 - \sqrt{25})^2}{|4 - 8|} = \dfrac{36-4\times4}4$

Now,

$36 = 9\times4$

so every term contains a factor of 4 that we can cancel:

$\dfrac{36-4\times4}4 = \dfrac{9\times4-4\times4}4 = \dfrac{9-4}1 = 9-4 = \boxed{5}$

as expected.