Question

What is the equation of a sine function with an amplitude of 2 and a period of 4π?

y = one-half sine (2 x)
y = one-half sine (4 pi x)
y = 2 sine (one-half x)
y = 2 sine (4 pi x)

Answer 1

The general equation

• y=Asin(Bx)

B is period and A is amplitude

• A=2

RearrAnge

• y=2sinBx

Period:-

• 2π/4π
• 2/4
• 1/2

So final equation

• y=2sin(1/2x)

Option C

Answer 2

Answer:

c

Step-by-step explanation:

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