The dimensions of the school yard is 58 m and 89 m.
A rectangle is a polygon with four sides , It has opposite sides parallel and equal.
It is given that
A rectangular school yard has a perimeter of 294 meters
Perimeter of a rectangle is given by
P = 2(Length +Breadth)
294 = 2( L+B)
147 = L+B
Area of a rectangle is given by
L*B = 5162
B = 5162/L
L + 5162/L =147
L² -147L +5162 = 0
L² -58L - 89L+5162 = 0
L(L-58) -89(L-58)
L = 58 , 89
The dimensions of the school yard is 58 m and 89 m.
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