The relation between the speed of impact and the dropping height is
[tex]\rm h =\dfrac{1}{2g}v^2[/tex]
What is Speed of Impact ?
It is defined as the speed of an object when it falls from a height and makes an impact with the ground or any other object.
As the object is falling from the height , its velocity will be continuously changing
Assuming it has no initial velocity , u = 0
let the final velocity is [tex]\rm v_f[/tex] = [tex]\rm \sqrt {2gh}[/tex]
the potential energy at the height h as mgh
the kinetic energy when it reaches the bottom as [tex]\rm \dfrac{1}{2}mv^2[/tex]
As the energy is always conserved
[tex]\rm mgh = \dfrac{1}{2}mv^2[/tex]
[tex]\rm h =\dfrac{1}{2g}v^2[/tex]
This is the relation between the speed of impact and the dropping height.
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