Question

Solve the following triangle. Round side measure to the nearest tenth and angle measure to the nearest degree:

Answer 1

Answer: $AB=4.7, BC=8.8, \angle C=28^{\circ}$

Step-by-step explanation:

As angles in a triangle add to 180 degrees,

$\angle C=180^{\circ}-90^{\circ}-62^{\circ}=\boxed{28^{\circ}}$

We know that:

$\sin 62^{\circ}=\frac{BC}{10}\\\\BC=10\sin 62^{\circ} \approx \boxed{8.8}$

Similarly,

$\cos 62^{\circ}=\frac{AB}{10}\\\\AB=10\cos 62^{\circ} \approx \boxed{4.7}$