Question

2/3 b + 5 =20 - b solve for b

Answer 1

Answer:

b = 9

Step-by-step explanation:

$\frac{2}{3} b + 5 = 20-b\\\frac{2}{3} b+5+b=20-b+b\\\frac{5}{3} b+5=20\\\frac{5}{3} b+5-5=20-5\\\frac{5}{3}b=15\\b= 15*\frac{3}{5} \\b= 9$

Answer 2

Answer:

$b = 9$

Step-by-step explanation:

$\frac{2}{3} b + 5 = 20 - b$

In order to solve for b, we must isolate the variable. We can start by subtracting 5 from both sides.

$\frac{2}{3} b + 5 - 5 = 20 - b - 5$

Simplify.

$\frac{2}{3} b = 15 - b$

Add b to both sides.

$\frac{2}{3} b + b = 15 - b + b$

Simplify.

$\frac{2}{3} b + b = 15$

Multiply everything by 3 to remove the fractions.

$3(\frac{2}{3}b+b) = 3(15)$

Simplify.

2b + 3b = 45

Simplify.

5b = 45

Divide 5 from both sides.

5b ÷ 5 = 45 ÷ 5

Simplify.

b = 9

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