Question

expand and simplify this 
can you help  
(2x²−3x+4) ( x²+5x−7) 

Answer 1

$(2x^2-3x+4) ( x^2+5x-7)= \\ \\=2x^2*x^2+2x^2*5x-2x^2*7-3x*x^2-3x*5x+3x*7+4*x^2+4*5x-4*7=\\ \\=2x^4+10x^3-14x^2 -3 x^3-15x^2+21x +4 x^2+20x-28=\\ \\=2x^4+7x^3-25x^2 +41x -28$