Find the value of x.
Round to the nearest tenth.
34
A
B
26°
x = [? ]°
X
C
15
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Answer: 83.5
Step-by-step explanation:
[tex]\frac{\sin x}{34}=\frac{\sin 26^{\circ}}{15} \\\\\sin x=\frac{34 \sin 26^{\circ}}{15}\\\\x=sin^{-1} \left(\frac{34 \sin 26^{\circ}}{15} \right) \approx \boxed{83.5}[/tex]
Answer:
x ≈ 83.5° or 96.5° (two possible values)
Step-by-step explanation:
The relationship between side lengths of a triangle and their opposite angles is given by the Law of Sines: side lengths are proportional to the sines of their opposite angles.
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In this problem, the Law of Sines tells us ...
sin(A)/BC = sin(C)/AB
sin(C) = sin(A)·AB/BC
Using x for angle C, solving for x, and using the inverse sine function, we find ...
x = arcsin(sin(26°)·34/15) ≈ arcsin(0.993641)
The arcsine function returns a value in the range 0–90°, but the supplemental angle in the rangle 90°–180° can have the identical sine value.
x ≈ 83.5° or 96.5°
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Additional comment
For the graph in the attachment, we have set the angle mode to degrees. The solutions to f(x)=0 are solutions to the problem: 83.5° and 96.5°.
The triangle in the figure appears to be an acute triangle. The value of x for an acute triangle would be 83.5°. Often, we cannot take these figures at face value.