A farmer has 324 feet of fencing to make three identical adjacent rectangular pens, as shown in the picture. What dimensions of each pen will maximize the total enclosed area?
![A farmer has 324 feet of fencing to make three identical adjacent rectangular pens as shown in the picture What dimensions of each pen will maximize the total e class=](https://us-static.z-dn.net/files/dab/5eca0ecbd4c42b2197754da0956979f2.png)
The dimensions of each pen will maximize the total enclosed area are: Length 81 feet; Width 81 feet.
Length = x
Width = y
Area = xy
Perimeter equation is
2(x + y) = 324
x + y = 162
Substituting the perimeter equation
Area = x(162 - x)
Area = -x2 + 162x
If the zeros of the quadratic are 0 and 162, then the median will be where the maximum area occurs.
162/ 2
= 81
Hence, the dimensions are
Length = 81 feet
Width = 162 - 81 = 81 feet
Therefore the dimensions of each pen will maximize the total enclosed area are: Length 81 feet; Width 81 feet.
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