Question

75m X A car moves with a uniform velocity 21 ms-1 from position P and a truck moves from rest with uniform acceleration 2 ms-2 from position Q in the same time in the same direction.

i) Determine the distance travelled in 20 seconds.
ii) How many times the private car will meet? Analyze mathematically.​

Answer 1

Velocity after 20s for both

• Car=21m/s
• Truck=2(20)=40m/s.

Distance traveled for car

• 20(21)=420m

Distance traveled by truck=

• s=ut+1/2at²
• s=1/2(2)(20)²
• s=400m

#b

Distance from Q

for car

• 420-75=345m

For truck

• 400m

The truck will meet the car after 75/21≈4s

Then for 6s the car keeps meeting because after 7 s Truck will archive 22m/s velocity

• Total meet ups=6+1=7times