Question

What is the distance between the points (-4,-8) and (6,16), to the nearest tenth of a units?
A. 8.2 units
B.676.0 units
C.21.8 units
D.26.0 units

Answer 1

Answer:

D.26.0 units

Step-by-step explanation:

Given : the points A(-4,-8) and B(6,16),

Let d be the distance between A and B.

Then

$d=\sqrt{\left( 16-\left( -8\right) \right)^{2} +\left( 6-(-4)\right)^{2} }$

  $=\sqrt{\left( 24\right)^{2} +\left( 10\right)^{2} }$

  $=\sqrt{676 }$

  $=26$