The volume of the water that was displaced will be equal to 0.06 cubic feet.
Suppose that a finite amount of substance is there having its properties as:
mass of substance = m kg
density of substance = d kg/m³
volume of that substance = v m³
Then, they are related as:
[tex]d = \dfrac{m}{v}[/tex]
If a prism is placed into a basin of water (density: 32.5 lb/ft3) and displaces 3.7 pounds of water, then the volume of the water that was displaced will be
We know that the density of the water is 62.4 pounds per cubic foot.
Then we get
3.7 = 62.4 × volume
Volume = 0.059
Volume ≅ 0.06 cubic-foot
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