Question

You have a solution of silver nitrate with an unknown concentration. To determine the concentration, you devise a method of adding an excess of calcium metal to 100.0 cm3 of solution and collecting the silver by filtration.

2AgNO3(aq)+Ca(s)→Ca(NO3)2(aq)+2Ag(s)

If 0.201 g of silver was collected, calculate the concentration of the silver nitrate solution in
mol dm−3.

Answer with the numerical value of the concentration to three significant figures, but do not include the units.

Answer 1

The concentration of the silver nitrate solution is 1.86 moles/dm³ .

What do you mean by concentration ?

The concentration of a substance is the quantity of solute present in a given quantity of solution.

2AgNO₃(aq)+Ca(s)→Ca(NO₃)₂(aq)+2Ag(s)

0.201 g of Silver = 0.201/107.8 = 0.00186 moles

From the equation we can see that for 2 moles of Silver to form we need 2 moles of silver nitrate .

For 0.00186 moles we will need 0.00186 moles of Silver nitrate

The concentration of the solution can be determined as

Molarity = moles / L of solution = 0.00186 moles/l

or 0.00186 moles/cu.cm = 1.86 moles/dm³

Therefore the concentration of the silver nitrate solution is 1.86 moles/dm³ .

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