Question

The z-score associated with 98% is 2.33. If the sample p-hat is 0.60 and the standard deviation is 0.02, find the lower limit of the 98% confidence interval.

Answer 1

Using the z-distribution, considering the given data, the lower limit of the 98% confidence interval is of 0.5534.

What is a z-distribution confidence interval?

The confidence interval is:

$p - zs$

In which:

• p is the sample proportion.

• z is the critical value.

• s is the standard error.

In this problem, the parameters are given as follows:

p = 0.6, z = 2.33, s = 0.02.

Hence, the lower limit of the 98% confidence interval is:

p - zs = 0.6 - 2.33 x 0.02 = 0.5534.

More can be learned about the z-distribution at https://brainly.com/question/25890103

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