Question

The brakes on a 17,600 N car exert a stopping force of 650. N. The car’s velocity changes from 25.0 m/s to 0 m/s.
a) What is the car’s mass?
b) What was its initial momentum?
c) What was the change in momentum for the car? d) How long does it take the braking force to bring the car to rest?

Answer 1

(a) The mass of the car is 1,795.92 kg

(b) The initial momentum of the car is 44,897.96 kgm/s.

(c) the change in momentum for the car is 44,897.96 kgm/s..

(d) The time it takes the braking force to bring the car to rest is 69.4 s.

Mass of the car

The mass of the car is calculated as follows;

W = mg

m = W/g

m = (17,600)/9.8

m = 1,795.92 kg

Initial momentum of the car

Pi = mvi

Pi = 1,795.92 x 25

Pi = 44,897.96 kgm/s

Change in momentum of the car

ΔP = Pf - Pi

ΔP = 0(1,795.92) - 44,897.96 kgm/s

ΔP =  - 44,897.96 kgm/s

Time taken for the car to come to rest

F = ma

-650 = 1,795.92(a)

a = -650/1,795.92

a = -0.36 m/s²

v = u + at

0 = 25 - 0.36t

0.36t = 25

t = 69.4 s

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