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What is the final temperature (in °C) of 120.1 g of water (specific heat = 4.184 J/g・°C) at 24.20°C that absorbed 950.0 J of heat?


i need help someone help me the chem 101 is due tomorrow

Respuesta :

From the calculations, the final temperature of the object is 26.1 °C.

What is specific heat capacity?

The specific heat capacity is defined as the temperature that is required to raise 1 Kg of a substance through a temperature rise  of 1 K.

When;

H = 950.0 J

T1 =  24.20°C

m = 120.1 g

c = 4.184 J/g・°C

T2 = ?

H = mc(T2 - T1)

950 = 120.1  * 4.184(T2 -  24.2)

950 = 502.5T2 - 12160.5

950 + 12160.5 = 502.5T2

T2 = 950 + 12160.5/502.5

T2 =  26.1 °C

Learn more about heat capacity:https://brainly.com/question/13499849

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