Three trains are made of identical train cars, so each car has the same number of seats. The first train has 418 seats, the second train has 456 seats, and the third train has 494 seats. How many cars are in each train if no train has more than 25 seats?

In my system the answer format is like this: There were cars in the first train, cars in the second train and __ cars in the third train

We know that the trains have 418, 456, and 494 seats. And are made of the same train cars, so the number of seats on each train car is a common factor of 418, 456 and 494.

We also know that no train car has more than 25 seats.

First, let's decompose the given numbers as a product of prime numbers:

418 = 2*11*19

456 = 2*2*2*3*19

494 = 2*13*19

As you can see, the factors 2 and 19 appear in the 3 numbers, 19 is the largest one that is also smaller than 25, so we conclude that each train car has 19 seats.

Then:

The first train, which has 418 seats, has:

418/19 = 22 train cars.

The second train has 456 seats, so it has:

456/19 = 24 train cars

The third train has 494 seats, so it has:

494/19 = 26 train cars.

If you want to learn more about common factors:

https://brainly.com/question/219464

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