Question

The current through a wire that is (1.8×10-2 m) long is (3.2 A). The wire is
perpendicular to a (7.5×10-2 T) magnetic field. What is the magnitude of the magnetic
force on the wire?

4.3×10 −3 N
5.8×10 −2 N
1.4×10 −3 N
2.4×10 −2 N

Answer 1

The magnitude of the magnetic force on the wire is determined as 4.32 x 10⁻³ N.

Magnetic force on the wire

The magnitude of magnetic force on the wire is calculated as follows;

F = BIL x sinθ

where;

B is magnetic field

• I is current
• L is length of the wire
• θ is angle of inclination

F = (7.5 x 10⁻²) x (3.2) x (1.8 x 10⁻²) x sin(90)

F = 4.32 x 10⁻³ N

Thus, the magnitude of the magnetic force on the wire is determined as 4.32 x 10⁻³ N.

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