Respuesta :

Step-by-step explanation:

Given,

[tex]x = {3}^{m} [/tex]

[tex]y = {3}^{n} [/tex]

Now

Consider

[tex] {3}^{4m - 1} [/tex]

We know that

[tex] \frac{ {a}^{p} }{ {a}^{q} } = {a}^{p- q} [/tex]

Using this we can write

[tex] {3}^{4m - 1} = \frac{ {3}^{4m} }{ {3}^{1} } [/tex]

[tex] = \frac{ {3}^{4m} }{3} [/tex]

We know that

[tex] ({a}^{p}) ^{q} = {a}^{pq} [/tex]

Using this we get

[tex] \frac{ {3}^{4m} }{3} = \frac{ ({3}^{m})^{4} }{3} [/tex]

Since we know that

[tex] {3}^{m} =x [/tex]

We get

[tex]= \frac{ {x}^{4} }{3} [/tex]

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