how do you do this question

Step-by-step explanation:
Given,
[tex]x = {3}^{m} [/tex]
[tex]y = {3}^{n} [/tex]
Now
Consider
[tex] {3}^{4m - 1} [/tex]
We know that
[tex] \frac{ {a}^{p} }{ {a}^{q} } = {a}^{p- q} [/tex]
Using this we can write
[tex] {3}^{4m - 1} = \frac{ {3}^{4m} }{ {3}^{1} } [/tex]
[tex] = \frac{ {3}^{4m} }{3} [/tex]
We know that
[tex] ({a}^{p}) ^{q} = {a}^{pq} [/tex]
Using this we get
[tex] \frac{ {3}^{4m} }{3} = \frac{ ({3}^{m})^{4} }{3} [/tex]
Since we know that
[tex] {3}^{m} =x [/tex]
We get
[tex]= \frac{ {x}^{4} }{3} [/tex]