The solution to the above function of summation (k - 1)! is determined as (n+1)P1.
Simplification of the function
The given expression can be simplified as follows;
∑(k - 1)!
Let's choose numbers;
(2 - 1)! = 1!
(3 - 1)! = 2!
(4 - 1)! = 3!
(5 - 1)! = 4!
(6 - 1) = 5! ----- + (n + 1)Pr
when n = 1
(1 + 1)P1 = 2P1 = (2 - 1)! = 1!
when n = 2
(2 + 1)P1 = 3P1 = (3 - 1)! = 2!
when n = 3
(3 + 1)P1 = 4P1 = (4 - 1)! = 3!
when n = 4
(4 + 1)P1 = 5P1 = (5 - 1) = 4!
Thus, the solution to the above function of summation (k - 1)! is determined as (n+1)P1.
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