Question

Find the sum of the first n terms using the formula a(1-r^n)/1-r $50 + $50(1.1) + 50(1.1)^2 + … (6 terms)

Answer 1

The sum of n terms is 500(1.1ⁿ - 1) and the sum of the 6th terms is 385.78

What is a sequence?

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

We have sequence:

50 + $50(1.1) + 50(1.1)^2 + …

The common ration r = 1.1

First term = 50

The sum of n terms:

$\rm Sum = \dfrac{50(1.1^n-1)}{1.1-1}\\\\\rm Sum = \dfrac{50(1.1^n-1)}{0.1}\\\\\\\rm Sum = 500(1.1^n-1)$

If n = 6 terms

Sum = 385.78

Thus, the sum of n terms is 500(1.1ⁿ - 1) and the sum of the 6th terms is 385.78

Learn more about the sequence here:

brainly.com/question/21961097

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