We have been given the two lengths as x and y So, the value of x would be equal to root 80.
How to obtain real measurements from the ratio of two measurements?
Suppose the real measurements were "a" and "b"
Then their ratio will be formed as
[tex]\dfrac{a}{b} = \dfrac{p \times x}{q \times x} = \dfrac{p}{q}[/tex]
where is a common factor (not 1)
This shows that to get the real measurements from the given ratio, we need to assume to have some factor possibly canceled from both the numerator and the denominator.
Thus, a = px, b = qx
we have been given the two lengths as x and y.
From the figure, we know that
11: y = y: 5
Express in fraction
11/y = y / 5
y^2 = 5(11)
y ^2 = 55
So, y = √55
From Pythagoras theorem;
[tex]x^{2} =5^{2} +y^{2} \\\\x^{2} =5^{2} +55 \\\\x^{2} =25 + 55\\\\x^{2} =80\\\\x = \sqrt{80}[/tex]
Learn more about ratios here:
brainly.com/question/186659
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