Sharon has a soap and water mixture that is 36% soap. How many liters of water must

Sharon add to 5 liters of this mixture to make a solution that is 12% soap?

Respuesta :

The volume of water that Sharon must add to the 5 liters mixture to make a solution that is 12% soap is 10 liters

Dilution law

From the question, we are to determine how many liters of water must Sharon add to 12% soap solution

Using the dilution law formula,

C₁V₁ = C₂V₂

Where C₁ is the initial concentration

V₁ is the initial volume

C₂ is the final concentration

and V₂ is the final volume

From the given information,

C₁ = 36%

V₁ = 5 liters

C₂ = 12%

V₂ = ?

Putting the parameters into the equation, we get

36 × 5 = 12 × V₂

180 = 12V₂

∴ V₂ = 180 / 12

V₂ = 15 liters

This means the final volume of the solution will be 15 liters.

Volume of water that must be added = V₂ - V₁

Volume of water that must be added = 15 liter - 5 liters

Volume of water that must be added = 10 liters

Hence, the volume of water that Sharon must add to the 5 liters mixture to make a solution that is 12% soap is 10 liters.

Learn more on Dilution law here: https://brainly.com/question/13407338

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