Question

Raj left home at 1 pm to travel 675km to visit his sister. he averaged 110km/h for the first part of the trip during which he had a 1 hour rest, and 90km/h for the second part of the trip during which he had a 30 minute rest. he reached his destination at 9pm. the number of minutes taken for the first part of the trip, to the nearest minute______

q9 pg 164 foundations of mathematics and pre-calculus 10

Answer 1

The time used for the first part of the trip in minutes is 270 minutes.

How to find the time used for the trip?

Total distance travelled = 675 km

He travelled from 1pm to 9pm.

He rested for 1 hour 30 minutes. The total time used for the trip is 6 hours 30 minutes.

let

the time used for the first part of the trip = x

Therefore,

speed = distance / time

distance = 110x

the time used for the first part of the trip = 6.5 - x

distance = 90(6.5 - x)

distance = 585 - 90x

Hence,

110x + 585 - 90x = 675

20x + 585 = 675

20x = 675 - 585

20x = 90

x  = 90 / 20

x = 4.5 hours = 270 minutes

Therefore, the time used for the first part of the trip is 270 minutes.

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