Question

Since the beginning of the month a local reservoir has been losing water at a constant rate. On the 10th of the month, the reservoir held 300million gallons of water and on the 18th it held only 262 million gallons. A. Write an equation that will give the amount of water in the reservoir at any time B. Hov, much water was in the reservoir on the 14th of the month? C. When will the reservoir get empty?​

Answer 1

1. An equation that will give the amount of water in the reservoir at any time is y = 300 million - 4.75x.
2. The water in the reservoir on the 14th day would be 281 million gallons.
3. The reservoir will be empty on the 63.16 day.

What is the equation that gives the amount of water in the reservoir?

Total amount in the reservoir = amount of water in the 10th month - (rate of decline x number of months from the 10th month)

Rate of decline = (300  262) / (18 - 10) = 4.75

y = 300 million = 4.75x

Where x is the time of the month.

What will be the quantity of water in the reservoir on the 14th of the month?

Total amount in the reservoir = amount of water in the 10th month - (rate of decline x number of months from the 10th month)

300 million - (4.75 x 4) = 281 million

When will the reservoir be empty?

0 = 300 - (4.75x)

x = 300 / 4.75

x = 63.16 days

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