What is the height, x, of the equilateral triangle shown?

Answer:
C. 10in
Step-by-step explanation:
[tex]\frac{sinA}{a} = \frac{sinB}{b}[/tex]
[tex]\frac{sin60}{10} = \frac{sin60}{x}[/tex]
[tex]x[/tex]sin60 = 10 × sin60
[tex]x[/tex]sin60 = [tex]5\sqrt{3}[/tex]
[tex]x[/tex] = [tex]\frac{5\sqrt{3} }{sin60}[/tex]
[tex]x[/tex] = 10in