Question

can someone help me with this 10th grade sector problem? This is 10th grade geometry, I will reward brainliest! Also please show your work!

Answer 1

Answer:

841854.7 ft²

Explanation:

$\sf Formula \ for \ area \ of \ sector = \dfrac{\theta}{360 } \ x \ \pi r^2$

Here given:

• θ = 60°

• radius (r) = 1268 ft

Hence solve for area of sector:

[Insert values]

$\rightarrow \sf \dfrac{60}{360 } \ x \ \pi (1268)^2$

[simplify]

$\rightarrow \sf 841854.6778$

[round to nearest tenth]

$\rightarrow \sf 841854.7$

Answer 2

Answer:

  841,854.7 ft²

Step-by-step explanation:

The area of the sector can be found using the appropriate area formula. The central angle in radians is required.

  A = 1/2r²θ . . . . where r is the radius, and θ is the central angle in radians

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The 60° angle corresponds to 60° × π/180° radians, or π/3 radians. The area of the 60° sector is then ...

  A = 1/2(1268 ft)²(π/3) = 803912/3π ft² ≈ 841,854.7 ft²

Devin does not have to plow an area of about 841,854.7 square feet.

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Additional comment

At 43560 ft² per acre, that's about 19.3 acres.