Please solve with explanation (high points)

The measure of the length GF is 4.2 units and IH is 2.27 units. Then the measure of angle ∠ACB will be 24.35°.
A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.
The triangle ΔABC and triangle ΔGFC are similar triangles. Then we have
GF / BA = CF / BC
GF / 5.62 = 8.88 / 12.42
GF = 4.018
GF ≅ 4.02
The triangle ΔABC and triangle ΔIHC are similar triangles. Then we have
IH / BA = HC / BC
IH / 5.62 = 5.02 / 12.42
IH = 2.271
IH ≅ 2.27
Then the angle ∠ACB will be
∠ACB = tan⁻¹ (5.62 / 12.42)
∠ACB = tan⁻¹ 0.452
∠ACB = 24.35°
More about the triangle link is given below.
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