Question

Consider an object of mass 2kg at rest on a ramp with βs=0.5 and βk=0.4.
If the ramp angle is 60 degrees, how far can the object travel in the first 1 seconds?

Answer 1

The distance traveled by the object in the first 1 second is determined as 0.98 m.

Distance traveled by the object

The distance traveled by the object is calculated as follows;

F - μkmgcosθ = ma

0 - μkmgcosθ = ma

- μkgcosθ = a

-(0.4)(9.8)cos60 = a

- 1.96 m/s² = a

s = ut + ¹/₂at²

s = 0(1) + ¹/₂(-1.96)(1)²

s = -0.98 m

|s| = 0.98 m

Thus, the distance traveled by the object in the first 1 second is determined as 0.98 m.

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