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Using the normal distribution, it is found that 16.43% of adults in the US qualify for stage 1.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

Researching the problem on the internet, the mean and the standard deviation are given, respectively, by:

[tex]\mu = 122, \sigma = 22[/tex].

The proportion of adults in the US qualify for stage 1 is the p-value of Z when X = 160 subtracted by the p-value of Z when X = 140, hence:

X = 160:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{160 - 122}{22}[/tex]

Z = 1.73

Z = 1.73 has a p-value of 0.9582.

X = 140:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{140 - 122}{22}[/tex]

Z = 0.82

Z = 0.82 has a p-value of 0.7939.

0.9582 - 0.7939 = 0.1643.

0.1643 = 16.43% of adults in the US qualify for stage 1.

More can be learned about the normal distribution at https://brainly.com/question/24663213

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