what is the approximate value of x in the exponential 4^x=14?

We know 4² = 16 , 4¹= 4
In this case we have :-
[tex] {4}^{x} = 14[/tex]
and we have to find the value of x
14 is less than 16 so x will be less than 2
14 is greater than 4 so x will be greater than 1
we can find the value of
[tex] {4}^{1.5} = {4}^{ \frac{3}{2} } \\ { (\sqrt{4}) }^{3} = {2}^{3} = 8[/tex]
so we can say 14 is much larger than 8 which means x will be much larger than 1.5
so according to above ideas we can say our answer is 2nd option which is 1.9037 is our answer
[tex]x \approx1.9037[/tex]
[tex]~~~~~~~4^x = 14 \\\\\implies \ln 4^x = \ln 14\\\\\implies x \ln 4 = \ln 14\\ \\\implies x = \dfrac{\ln 14}{ \ln 4}\\\\\implies x \approx 1.9037[/tex]