Question

solubility constant 5
For the dissolving of CaF2, the equilibrium constant expression, Ksp, is
Select one:
O Ksp = [Ca2+] [F]²
Ksp = [Ca2+] [F] / [CaF₂]
O Ksp = [Ca²+] [F]
O
Ksp = [Ca2+] [F]²/[CaF₂]
O
Ksp = [CaF₂] / ([Ca²+] [F] ²)

Answer 1

The Ksp of the compound CaF2 is given as; Ksp = [Ca2+] [F]²

What is solubility product?

The term solubility product has to do with the extent to which a substance dissolves in solution.

For the compound CaF2, we have; CaF2(s) ⇆Ca^2+(aq) + 2F^-(aq). Hence, the Ksp of the solution is  Ksp = [Ca2+] [F]²

Learn more about Ksp:https://brainly.com/question/27132799

#SPJ1