Respuesta :
Answer:
613.5 pm
Explanation:
We know that de Broglie wavelength of an electron :
λ = 1.227 / √E nm
λ = 1.227 / √400 nm
λ = 1.227 / 20 nm
λ = 0.6135 nm
λ = 0.6135 x 10⁻⁹ m
λ = 613.5 x 10⁻¹² m
λ = 613.5 pm
Wavelength
Wavelength of election having kinetic energy of 400 ev.
Solution:
- WE = 1.227 / √election nm
- WE = 1.227 / √e400nm
- WE = 1.227 / √20nm
- WE = 0.6136nm
- WE = 0.6136 x 10-⁹m
- WE = 613.5 x 10-¹²m
- WE = 613.5