Question

A rectangular fence is to a total perimeter of 200 feet. If the length is twice the width, find the measurements of the length and width of the rectangular fence.

Answer 1

✪ Question -:

A rectangular fence is to a total perimeter of 200 feet. If the length is twice the width, find the measurements of the length and width of the rectangular fence.

✪ Explanation -:

In this question we are provided with the perimeter of a rectangle fence that is 200 feet. It is also given that the length of the fence is twice its breadth. We are asked to calculate it's dimensions.

First we will form an equation.

Let us assume the breadth as x

Then, length = 2x

It is given that the perimeter is 200 feet.

We know,

$\bull \: \small\boxed{ \rm{ Perimeter_{(rectangle)} = 2(length + breadth)}}$

Substituting the values we get

$\small\sf{ 200 = 2(2x + x)}$

Now we will solve this equation and find out the value of x.

$\small\sf{ 200 = 2(2x + x)}$

$\longmapsto \small\rm{ 200 = 2(3x )}$

$\longmapsto \small\rm{200 = 6x}$

$\longmapsto \small\rm{ \dfrac{ \cancel{200} \: \: 33.33}{ \cancel{6}} = x }$

$\small\sf{x = 33.33}$

We will substitute the value of x = 33.33.

Length = 2x = 2 × 33.33 = 66.66 feet

Breadth = x = 33.33 feet

• Hence the length of the rectangular fence is 66.66 feet and the breadth is 33.33 feet.