Question

please solve the problem

I want whole process​

Answer 1

Answer:

1

Step-by-step explanation:

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⠀⠀⠀⠀□ Question

$\Large \frac{ {x}^{p(q - r)} }{ {x}^{q(p - r)} } \div {( \frac{ {x}^{q} }{{x}^{p} } })^{r}$

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⠀⠀⠀⠀■ Solution

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• Multiplying the power

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$\sf \Large{ \frac{ {x}^{pq - pr} }{ {x}^{pq - qr} } } \div \frac{ {x}^{qr} }{ {x}^{pr} }$

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• Changing ÷ sign into × by doing reciprocal

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$\sf\Large{ \frac{ {x}^{pq - pr} }{ {x}^{pq - qr} } } \times \frac{ {x}^{pr} }{ {x}^{qr} }$

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• As the base(x) is same, if the value is multipying so the power will add, if the value is dividing so the power will subtract.

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$\sf {x}^{pq - pr - pq + qr} \times {x}^{pr - qr} \\ \\ \sf {x}^{qr - pr} \times {x}^{pr - qr} \\ \\ \sf {x}^{qr - qr + pr - pr}$

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• If the power of any value become 0,so it's value is always equal to 1

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$\sf \Large{ {x}^{0} } \\ \\ \boxed {\large {\rightarrow1 }}$

Answer 2

Answer:

1

Step-by-step explanation:

Solving :

⇒ $\frac{x^{p(q-r)} }{x^{q(p-r)} }$ ÷ $(\frac{x^{q} }{x^{p} })^{r}$

⇒ $\frac{x^{p(q-r)} }{x^{q(p-r)} }$ ÷ $[ ({x^{q-p} })^{r}| or| x^{r(q-p)} ]$

⇒ ${x}^{pq-pr-qp+qr}$ ÷ $x^{rq-rp}$

⇒ $x^{pq-pq+qr-qr+pr-pr}$

⇒ x⁰

⇒ 1