Question

An object is launched at an initial velocity of 19.6 meters per second from an initial height of 24.5 meters. which equation can be used to find the number of seconds it takes the object to hit the ground? 0 = –4.9t2 19.6t 24.5 0 = –4.9t2 24.5t 19.6 19.6 = –4.9t2 24.5t 24.5 = –4.9t2 19.6t

Answer 1

Check the picture below.

$~~~~~~\textit{initial velocity in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&19.6\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&24.5\\ \qquad \textit{of the object}\\ h=\textit{object's height}&h\\ \qquad \textit{at "t" seconds} \end{cases} \\\\\\ h(t)=-4.9t^2+19.6t+24.5\hspace{5em}\stackrel{\textit{when it hits the ground}}{0=-4.9t^2+19.6t+24.5}$

Answer 2

Answer:

its A

Step-by-step explanation:

ifunny is dankreloaded