Question

Question:

the initial pressure of a 4.0 l sample of helium gas is measured to be 12 atm.

if the pressure of the sample is reduced 3.0 atm, what is the resulting volume?

options:
a. 12l

b. 16l

c. 1.0 l

d. 9.0 l

Answer 1

Answer:

B

Explanation:

Recall the ideal gas law:

$\displaystyle PV = nRT$

Because n, R, and T remain constant, we can rewrite the equation as:

$\displaystyle k = P_1V_1 = P_2V_2$

Where k is some constant. This form of the ideal gas law is referred to as Boyle's Law.

Substitute and evaluate:

$\displaystyle \begin{aligned} (4.0\text{ L})(12\text{ atm}) & = (3.0\text{ atm})V_2 \\ \\ V_2 & = 16\text{ L} \end{aligned}$

In conclusion, the answer is B .