Respuesta :

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's evaluate ~

[tex]\qquad \sf  \dashrightarrow \:f(x) =- 8x + 14 + 15 {x}^{2} [/tex]

we have to find value of f(-3), so plug the value of x as -3 in the equation ~

[tex]\qquad \sf  \dashrightarrow \:f( - 3) =- 8( - 3) + 14 + 15 {( - 3)}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:f( - 3) = 24 + 14 + 15 {(9)}^{} [/tex]

[tex]\qquad \sf  \dashrightarrow \:f( - 3) = 38+ 135 [/tex]

[tex]\qquad \sf  \dashrightarrow \:f( - 3) = 173 [/tex]

I hope it's easy to understand now ~

f(-3):

[tex]\\ \rm\Rrightarrow 15x²-8x+14[/tex]

[tex]\\ \rm\Rrightarrow 15(-3)²-8(-3)+14[/tex]

[tex]\\ \rm\Rrightarrow 15(9)+24+14[/tex]

[tex]\\ \rm\Rrightarrow 135+38[/tex]

[tex]\\ \rm\Rrightarrow 173[/tex]

ACCESS MORE
EDU ACCESS