Question

Select the correct answer. how many atoms of n are in 137.0 grams of n2o3? a. 1.085 × 1023 b. 1.802 × 1023 c. 5.985 × 1023 d. 2.171 × 1024 e. 3.604 × 1024

Answer 1

The Number of atoms of N in 137.0 grams of Dinitrogen trioxide (N₂O₃) is 2.171 × 10²⁴ atoms.

Option D) 2.171 × 10²⁴ is the correct answer.

How many atoms of N are in 137.0 grams of N₂O₃?

Given that;

• Mass of N₂O₃ = 137.0g
• Atoms of N in 137.0 grams of N₂O₃ = ?

First we determine the moles of N₂O₃.

Molar mass of Dinitrogen trioxide N₂O₃ is 76.01 g/mol.

Hence,

Number of moles of N₂O₃  = Mass / Molar Mass

Number of moles of N₂O₃  = 137.0g / 76.01g/mol

Number of moles of N₂O₃ = 1.80239mol

N = 1.80239mol × Avogadro's Number

N = 1.80239mol × ( 6.022 × 10²³mol⁻¹ )

N = 1.085399 × 10²³molecules

Since 1 molecule of N₂O₃ contains 2 atoms of Nitrogen and 3 atoms of Oxygen.

Number of atoms of N = 2 × (1.085399 × 10²³molecules)

Number of atoms of N = 2.171 × 10²⁴ atoms

The Number of atoms of N in 137.0 grams of Dinitrogen trioxide (N₂O₃) is 2.171 × 10²⁴ atoms.

Option D) 2.171 × 10²⁴ is the correct answer.

Learn more about relationship between mole and Avogadro’s number here: https://brainly.com/question/1445383

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