Question

Please belpppp don’t understand

Answer 1

Answer:

$\huge 3w^2\sqrt[4]{2\:w^{3}}$

Step-by-step explanation:

• $\huge\sqrt[4]{162\:w^{11}}$

• $=\huge\sqrt[4]{81*2\:w^{8}*w^{3}}$

• $=\huge\sqrt[4]{3^4*2\:(w^{2})^4*w^{3}}$

• $=\huge 3w^2\sqrt[4]{2\:w^{3}}$ (Elements with power 4 within the radical will come out and the rest will be within the radical sign)