Question

Can someone help me with this question?

A bag contains 12 movie tickets and 8 concert tickets. You randomly choose 1 ticket and do not replace it. Then you randomly choose another ticket. Find the probability that both events A and B will occur. Round your answer to the nearest tenth.

Event A: The first ticket is a concert ticket.

Event B: The second ticket is a concert ticket.

about ___%.

Answer 1

To solve this problem, we have to understand probability without replacement and consider the two events happening. The probability that both events occurs is 14%

Probability without replacement

To solve this problem, let's write down the data given;

Data;

• Movie Ticket = 12
• Concert Ticket = 8

But we are asked to calculate the probability that both times we pick both tickets, it would be a concert ticket.

Total number of tickets =

$12 + 8 = 20$

Let's proceed for the first event

$P = \frac{8}{20}= \frac{2}{5}$

The probability the second event occurs will be

$P = \frac{7}{20}$

The probability both events occur will be

$P = P_a * P_b = \frac{2}{5} * \frac{7}{20} = \frac{7}{50} =0.14 = 14\%$

The probability that both events occurs is 14%

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