To solve this problem, we have to understand probability without replacement and consider the two events happening. The probability that both events occurs is 14%
To solve this problem, let's write down the data given;
Data;
But we are asked to calculate the probability that both times we pick both tickets, it would be a concert ticket.
Total number of tickets =
[tex]12 + 8 = 20[/tex]
Let's proceed for the first event
[tex]P = \frac{8}{20}= \frac{2}{5}[/tex]
The probability the second event occurs will be
[tex]P = \frac{7}{20}[/tex]
The probability both events occur will be
[tex]P = P_a * P_b = \frac{2}{5} * \frac{7}{20} = \frac{7}{50} =0.14 = 14\%[/tex]
The probability that both events occurs is 14%
Learn more on Probability without replacement here;
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