The maximum amount, in grams, of Fe that would be produced during the experiment, will be 280 grams
From the equation of the reaction:
[tex]Fe_2O_3 + 2Al -- > 2Fe + Al_2O_3[/tex]
The mole ratio of [tex]Fe_2O_3[/tex] to Al is 1:2.
But 3 moles and 5 moles of reactants respectively started the reaction. Thus, Al is limited in availability and will determine the amount of products that will be produced.
The mole ratio of Al and Fe is 1:1, therefore, a maximum of 5 moles of Fe will be produced from the reaction.
5 moles Fe = 5 x 56 = 280 grams
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