Question

What volume (in mL) of 0.750 M sodium hydroxide is needed to neutralize (react with) 275 ml of 0.500 M sulfuric acid (H2SO4)? Write your answer with the proper number of sig figs. Balance the equation first.Your answer will be in mL

NaOH + H2SO4 -> H2O + Na2SO4
I need workkkk

Answer 1

2NaOH+ H2SO4= Na2SO4+2H2O
_ we have C[NaOH]= 0.750M, V[H2SO4]=250ml, C[H2SO4]=0.500M
_ n[H2SO4]= c.v = 0.500x250=125mol
So n[NaOH]= 2n[H2SO4]
= 2x125mol=250mol
So V[NaOH]= n/c = 250ml/0.750M= 333.33ml