Question

two boys decided to buy a computer. The second boy had 5/6 of the amount of money the first had. The first boy had 7/8 of the price of the computer. Together they had $696 more than they needed to pay. What was the price of the computer

Answer 1

Answer:

1152$

Step-by-step explanation:

b1 = 7/8 C

b2 = 5/6 b1 = 35/ 48 C

7/8 C + 35/48 C = C + 696

42/48 C + 35/48 C = 48/48 C + 696 * 48/48

(42 + 35 - 48 ) C = 696 * 48

29 C = 33408

C =1152.