Question

Find the vertex of this parabola. y = -2x2 4x 12 a. (-4, 12) b. (-2, 6) c. (3, 6) d. (1, 14)

Answer 1

We will see that the vertex of the quadratic equation is at (1, 14)

How to find the vertex of a quadratic function?

For a general quadratic:

$y = a*x^2 + b*x + c$

The x-component of the vertex is at:

$x = -b/2a$

In this case, we have:

$y = -2x^2 + 4x + 12$

Then the vertex is at:

$x = -4/(2*-2) = 1$

To get the y-component of the vertex, we need to evaluate in x = 1.

$y = -2*1^2 + 4*1 + 12 = -2 + 4 + 12 = 14$

Then we conclude that the vertex is at (1, 14), so the correct option is d.

If you want to learn more about quadratic equations:

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