The two slits are at a distance of 40.11 μm. The distance is found by the relation,mλ=dsinθ.
Diffraction occurs when waves, such as light or sound, spread out when they pass through a slit or around an object.
The formula of the wavelength is;
[tex]\rm \lambda= \frac{c}{v} \\\\ \lambda=\frac{3 \times 10^8 }{6.37 \times 10^{14}} \\\\ \lambda= 471 \ nm[/tex]
The distance between the two slits is calculated by the relation;
[tex]\rm m \times \lambda= d sin \theta \\\\ d= \frac{m \times \lambda}{sin \theta} \\\\ d= \frac{3 \times 471 \times 10^{-9} \times 88.0 \times 10^{-2}}{3.10 \times 10^{-2}} \\\\ d=40.11 \times 10^{-6} \ m \\\\ d=40.11 \mu m[/tex]
Hence,the two slits are at a distance of 40.11 μm.
To learn more about the two-slit diffraction of light refer to the link;
brainly.com/question/16046466
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